(Q58282865)

English

On the difference equationxn+1=Af(xn) +f(xn−1)

article published in 2004

Statements

On the difference equationxn+1=Af(xn) +f(xn−1) (English)
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G.L. Karakostas
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S. Stević
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March 2004
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83
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309-323
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3
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