Jona

Welcome to Wikidata, Jona!

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Best regards! Liuxinyu970226 (talk) 00:10, 14 May 2015 (UTC)

Request a query

Shame - I had answers for you. Fancy putting it back - your second query is a very good example of an issue quite a lot of people will have. --Tagishsimon (talk) 21:48, 19 December 2018 (UTC)

@Tagishsimon: I think that I found it :

SELECT ?item ?itemLabel ?party ?partyLabel ?partycount where
{ {SELECT ?item (count(?party) as ?partycount) WHERE {
  ?item p:P39 ?statement.
  ?statement ps:P39 wd:Q17781726.
  ?statement pq:P2937 wd:Q30544772 .
  ?item wdt:P102 ?party.
  MINUS { ?statement pq:P4100 ?group } .
}
 group by ?item } .
 ?item wdt:P102 ?party .
 FILTER (?partycount=1)
 SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],de". }

 }

Try it!

We can restore the subject for reference if you want ! ;) Jona (talk) 21:53, 19 December 2018 (UTC)

No, we're good. Someone else will dial in the problem sometime. I will remind you of having (?partycount=1) which is an alternative to your filter; and do much what you've just done above, but with a named subquery rather than a nested query.

SELECT ?item ?itemLabel ?partyLabel  with {
  select DISTINCT ?item (count(?party) as ?partycount) WHERE {
  ?item p:P39 ?statement.
  ?statement ps:P39 wd:Q17781726.
  ?statement pq:P2937 wd:Q30544772 .
  ?item wdt:P102 ?party.
  MINUS { ?statement pq:P4100 ?group } .
} group by ?item having (?partycount=1) } as %items
where
{
  include %items
  SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],de". }
}

Try it!

--Tagishsimon (talk) 21:57, 19 December 2018 (UTC)