(Q14634618)

English

Pardomuan

subdistrict in South Tapanuli Regency, North Sumatra, Indonesia

In more languages

default for all languages

No label defined

No description defined

edit

Statements

instance of

kelurahan

1 reference

stated in

Indonesian Minister of Home Affairs Decree 100.1.1-6117 Of 2022

page(s)

352

country

Indonesia

3 references

imported from Wikimedia project

Indonesian Wikipedia

stated in

Indonesian Minister of Home Affairs Decree Number 050-145 of 2022

stated in

Indonesian Minister of Home Affairs Decree 100.1.1-6117 Of 2022

page(s)

352

located in the administrative territorial entity

South Angkola

2 references

stated in

Indonesian Minister of Home Affairs Decree Number 050-145 of 2022

stated in

Statistics Indonesia Regulation Number 5 Of 2021

subject named as

Kelurahan Pardomuan

page(s)

78

object stated in reference as

Kecamatan Angkola Selatan

located in time zone

UTC+07:00

0 references

coordinate location

1°18'0.000"N, 99°5'52.800"E

0 references

Statistics Indonesia area code

1203080001

2 references

subject named as

Kelurahan Pardomuan

retrieved

6 June 2023

reference URL

https://sig.bps.go.id/bridging-kode/

stated in

Statistics Indonesia Regulation Number 5 Of 2021

Kelurahan Pardomuan

78

0 references

Identifiers

administrative code of Indonesia

12.03.06.1019

2 references

reference URL

http://www.kemendagri.go.id/media/filemanager/2015/08/18/1/2/12._sumut.pdf

stated in

Indonesian Minister of Home Affairs Decree Number 050-145 of 2022

Google Knowledge Graph ID

/g/12h2t0bsp

0 references

/g/1pwgtblny

0 references

Sitelinks

Wikipedia(3 entries)

idwiki Pardomuan, Angkola Selatan, Tapanuli Selatan
nlwiki Kelurahan Pardomuan
suwiki Pardomuan, Angkola Selatan, Tapanuli Kidul

(Q14634618)

Pardomuan

Statements

Identifiers

Sitelinks

Wikipedia(3 entries)

Wikibooks(0 entries)

Wikinews(0 entries)

Wikiquote(0 entries)

Wikisource(0 entries)

Wikiversity(0 entries)

Wikivoyage(0 entries)

Wiktionary(0 entries)

Multilingual sites(0 entries)