[Haskell-beginners] How to divide a pair of Num values?
Costello, Roger L.
costello at mitre.org
Wed Oct 24 11:01:34 CEST 2012
Hi Folks,
Here is a function that takes a pair of Integral
values and divides them:
divide_v1 :: Integral a => (a, a) -> a
divide_v1 (m, n) = (m + n) `div` 2
I invoke the function with a pair of Integral
values and it works as expected:
divide_v1 (1, 3)
Great. That's perfect if my numbers are always Integrals.
Here is a function that takes a pair of Fractional
values and divides them:
divide_v2 :: Fractional a => (a, a) -> a
divide_v2 (m, n) = (m + n) / 2
I invoke the function with a pair of Fractional
values and it works as expected:
divide_v2 (1.0, 3.0)
Great. That's perfect if my numbers are always Fractionals.
I would like a function that works regardless of whether the
numbers are Integrals or Fractionals:
divide_v3 :: Num a => (a, a) -> a
divide_v3 (m, n) = (m + n) ___ 2
What operator do I use for ___?
Thanks.
/Roger
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